8x^2+56x+96=0

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Solution for 8x^2+56x+96=0 equation:



8x^2+56x+96=0
a = 8; b = 56; c = +96;
Δ = b2-4ac
Δ = 562-4·8·96
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8}{2*8}=\frac{-64}{16} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8}{2*8}=\frac{-48}{16} =-3 $

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